From
pastilla: How many oz of 40% alcohol must be mixed with 10 oz of 70% alcohol to give a solution that is 45% alcohol? (fun GRE question)After initially stumbling over the same basic subtraction as
dblume (like, 7 - 4.5 = two point five, duh....) I solved the problem this way:.4x + .7(10) = .45(10+x)
.4x + 7 = .45(10+x)
.4x + 7 = 4.5 + .45x
.4x = -2.5 + .45x
.05x = 2.5
x = 50 oz
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Yup, really did.
I guess that's why they named us Duh-vid!
Edited at 2008-12-11 06:41 am (UTC)
:: large Sanrio sticker ::
:: assembles Pyrex cup, Everclear, lemon wedges ::
Mix 10 at 70% with 10 at 40% ... nope, that's 55%, won't do so drink it.
Mix 10 at 70% with 20 at 40% ... nope, 50% is still to uch. Drink it.
Mix 10 at 70% with 30 at 40% ... (hips), 47 and a bit ... Yay, drink it.
Mhix 1o t 70& wih 40 at 40 ... hihi forty 'n six, yezzz, nother round.
hix then at ... high with 50 at lo ... (hips) ... oops dranked tho earli moust try hagain ...
Mihix 1..0 at se ve ...
*thunk*
ZZzzzzz .... snore... snore...
(so you need 150oz at 40% and 50oz at 70% to get the right mix ... and you only know the answer the morning after ^_~ )
Edited at 2008-12-11 08:48 pm (UTC)